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Math Help - Another second derivatives question. :(

  1. #1
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    Another second derivatives question. :(

    Struggling with another question.

    f(x)= sinh^-1 (5x)

    Then i went to this

    f'(x)= 5 (1/(1-5(x))^2)

    Not sure what to do after that.

    Thanks in advance
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  2. #2
    MHF Contributor Amer's Avatar
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    ok
    f(x)=sinh^{-1}(5x)
    f'(x)= \frac{(5x)'}{1+(5x)^2}=\frac{5}{1+25x^2}=5(1+25x^2  )^{-1}
    f''(x)= this..... for..... you....<br />
    Last edited by Amer; May 31st 2009 at 10:18 AM.
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  3. #3
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    f''(x)= -5 (50x) (1+25x^2)^-2

    Is that correct for the second derivatives?

    Cheers
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  4. #4
    MHF Contributor Amer's Avatar
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    Yeah it is correct
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