Struggling with another question. $\displaystyle f(x)= sinh^-1 (5x)$ Then i went to this $\displaystyle f'(x)= 5 (1/(1-5(x))^2)$ Not sure what to do after that. Thanks in advance
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ok $\displaystyle f(x)=sinh^{-1}(5x) $ $\displaystyle f'(x)= \frac{(5x)'}{1+(5x)^2}=\frac{5}{1+25x^2}=5(1+25x^2 )^{-1}$ $\displaystyle f''(x)= this..... for..... you.... $
Last edited by Amer; May 31st 2009 at 10:18 AM.
$\displaystyle f''(x)= -5 (50x) (1+25x^2)^-2$ Is that correct for the second derivatives? Cheers
Yeah it is correct
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