Find both the first and second derivatives of the the function:
$\displaystyle f(x) = tan^-1 3x $
I started by doing
$\displaystyle dy/dx = 3* 1/1+(3x)^2$
Then $\displaystyle 3/(1+9x^2)$
Can anyone finish this off for me please.
Thanks in advance
Find both the first and second derivatives of the the function:
$\displaystyle f(x) = tan^-1 3x $
I started by doing
$\displaystyle dy/dx = 3* 1/1+(3x)^2$
Then $\displaystyle 3/(1+9x^2)$
Can anyone finish this off for me please.
Thanks in advance