Q) At what integral value of x will the function (x^2 + 3x + 1)/(x^2 -3x+1) attains its maximum value? Any help would be greatly appreciated. Thanks, Ashish
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simplify the function-> you will see that when x=1,it attains max and when x=-1,it attains min.
How do you simplify the above expression to 1+(6/(x-3+1/x)) ?
the critical points (3+5^1/2)/2 and (3-5^1/2)/2 since (x^2 +3x+1)/(x^2 -3x+1)=(x^2-3x+1 +6x)/(x^2-3x+1) = 1+6x/(x^2-3x+1) = 1+6(x-3+1/x)^-1= f(x) f`(x) = -1 (1 -1/x^2)(x-3+1/x)^-2 = 0 the root of the numerator {-1,1} and the root denominator but the denominator is always positive look at this
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