[SOLVED] Double Integral over region

**juicysharpie** · May 29th 2009, 02:37 PM

Hi, I'm really confused with where to start. I integrated with respect to x first, so that I could plug in y and 0 and then integrate with respect to y after, but I keep getting 0 as an answer after plugging in y and 0.

This is what I got when I integrated with respect to x..
(7x/6)(y^2-x^2)^(3/2)

**Spec** · May 29th 2009, 02:51 PM

$\int_0^y \left( 7x\sqrt{y^2-x^2} \right)dx=\left[-\frac{7}{3}(y^2-x^2)^{3/2}\right]_0^y$

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[SOLVED] Double Integral over region

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