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Math Help - [SOLVED] Double Integral over region

  1. #1
    Junior Member
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    Jan 2009
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    [SOLVED] Double Integral over region



    Hi, I'm really confused with where to start. I integrated with respect to x first, so that I could plug in y and 0 and then integrate with respect to y after, but I keep getting 0 as an answer after plugging in y and 0.

    This is what I got when I integrated with respect to x..
    (7x/6)(y^2-x^2)^(3/2)
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  2. #2
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    \int_0^y \left(  7x\sqrt{y^2-x^2}  \right)dx=\left[-\frac{7}{3}(y^2-x^2)^{3/2}\right]_0^y
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