Hi. A troubling question I have here
Using integration by parts, show that if $\displaystyle I=\int\sqrt{1-x^2}dx$, that
$\displaystyle I=x\sqrt{1-x^2} -I + \int\frac{1}{\sqrt{1-x^2}}dx$
Hi. A troubling question I have here
Using integration by parts, show that if $\displaystyle I=\int\sqrt{1-x^2}dx$, that
$\displaystyle I=x\sqrt{1-x^2} -I + \int\frac{1}{\sqrt{1-x^2}}dx$