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Math Help - Integration by parts

  1. #1
    Senior Member I-Think's Avatar
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    Integration by parts

    Hi. A troubling question I have here
    Using integration by parts, show that if I=\int\sqrt{1-x^2}dx, that

    I=x\sqrt{1-x^2} -I + \int\frac{1}{\sqrt{1-x^2}}dx
    Last edited by I-Think; May 29th 2009 at 01:18 AM.
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  2. #2
    MHF Contributor Amer's Avatar
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    Integration by parts-nwe.jpg
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  3. #3
    Senior Member I-Think's Avatar
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    Thanks for the help, I didn't think of working it backwards. I'm just confused on one point

    1) How does \int\frac{1-x^2+1}{\sqrt{1-x^2}}dx become \int\frac{-x^2}{\sqrt{1-x^2}}dx<br />
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  4. #4
    MHF Contributor Amer's Avatar
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    ohh
    i see there is a negative , I forget to enter it in the integral so

    -1 +x^2 +1 = x^2
    Last edited by Amer; May 29th 2009 at 07:06 AM.
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