can someone help me get the general solution for this..I get confused about the derivative of x 9d^2x/dt^2+6dx/dt+x=0 ,X(-3)=2 ,dx/dt(-3)=1/2 I get x(t)=(C1+C2t)e^-1/3t I cannot seem to get the answers for the initial conditions above..
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Originally Posted by Raidan can someone help me get the general solution for this..I get confused about the derivative of x 9d^2x/dt^2+6dx/dt+x=0 ,X(-3)=2 ,dx/dt(-3)=1/2 I get x(t)=(C1+C2t)e^-1/3t I cannot seem to get the answers for the initial conditions above.. I'm not sure that I understand. Is this what you have? where is the second derivative of x with respect to t; and x is a function of t and x(-3)=2?
Originally Posted by VonNemo19 I'm not sure that I understand. Is this what you have? where is the second derivative of x with respect to t; and x is a function of t and x(-3)=2? yes thats what I mean..hw would i do this
oo and with the other intial condition x''(-3)=1/2
Originally Posted by Raidan can someone help me get the general solution for this..I get confused about the derivative of x 9d^2x/dt^2+6dx/dt+x=0 ,X(-3)=2 ,dx/dt(-3)=1/2 I get x(t)=(C1+C2t)e^-1/3t I cannot seem to get the answers for the initial conditions above.. So this is a 2nd order linear ODE with constant coeffeints so the auxillary equaiton is So we have one repeated root. So we multiply by t to get the 2nd linearly independant solution. Now we can use IC to find the constants
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