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Math Help - Using the General Power rule to find the derivative

  1. #1
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    Using the General Power rule to find the derivative

    Use the general power rule to find the derivative of the function:

    y=\sqrt[3]{3x^3}{+4x}

    Need some assistance solving down using the General Power Rule. Thanks.


    EDIT: The SqRt I messed up the LaTex it's suppose to be everything square rooted. The +4x is suppose to be included in it...
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  2. #2
    Member Nacho's Avatar
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    <br />
\left( {\sqrt[3]{{3x^3  + 4x}}} \right)^\prime   = \frac{1}<br />
{3}\left( {3x^3  + 4x} \right)^{\frac{1}<br />
{3} - 1}  \cdot \left( {3x^3  + 4x} \right)^\prime   = \frac{1}<br />
{3}\left( {3x^3  + 4x} \right)^{ - 2/3}  \cdot \left( {6x^2  + 4} \right)<br />

    P.D: power rule=chain rule?
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  3. #3
    Senior Member Spec's Avatar
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    Quote Originally Posted by Nacho View Post
    <br />
\left( {\sqrt[3]{{3x^3  + 4x}}} \right)^\prime   = \frac{1}<br />
{3}\left( {3x^3  + 4x} \right)^{\frac{1}<br />
{3} - 1}  \cdot \left( {3x^3  + 4x} \right)^\prime   = \frac{1}<br />
{3}\left( {3x^3  + 4x} \right)^{ - 2/3}  \cdot \color{red}{ \left({6x^2  + 4} \right)}<br />

    P.D: power rule=chain rule?
    The part in red isn't correct.
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  4. #4
    Member Nacho's Avatar
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    Quote Originally Posted by Spec View Post
    The part in red isn't correct.
    ajajaj 3x3=6

    sorry
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