# Thread: Using the General Power rule to find the derivative

1. ## Using the General Power rule to find the derivative

Use the general power rule to find the derivative of the function:

$y=\sqrt[3]{3x^3}{+4x}$

Need some assistance solving down using the General Power Rule. Thanks.

EDIT: The SqRt I messed up the LaTex it's suppose to be everything square rooted. The +4x is suppose to be included in it...

2. $
\left( {\sqrt[3]{{3x^3 + 4x}}} \right)^\prime = \frac{1}
{3}\left( {3x^3 + 4x} \right)^{\frac{1}
{3} - 1} \cdot \left( {3x^3 + 4x} \right)^\prime = \frac{1}
{3}\left( {3x^3 + 4x} \right)^{ - 2/3} \cdot \left( {6x^2 + 4} \right)
$

P.D: power rule=chain rule?

3. Originally Posted by Nacho
$
\left( {\sqrt[3]{{3x^3 + 4x}}} \right)^\prime = \frac{1}
{3}\left( {3x^3 + 4x} \right)^{\frac{1}
{3} - 1} \cdot \left( {3x^3 + 4x} \right)^\prime = \frac{1}
{3}\left( {3x^3 + 4x} \right)^{ - 2/3} \cdot \color{red}{ \left({6x^2 + 4} \right)}
$

P.D: power rule=chain rule?
The part in red isn't correct.

4. Originally Posted by Spec
The part in red isn't correct.
ajajaj 3x3=6

sorry