r(t) = cos(2t) + 3sin(2t) t=0
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Is it $\displaystyle r(t) = \cos 2t + 3t \sin 2t $?
nope r(t) = cos(2t)i + 3sin(2t)j t=0
Let $\displaystyle x = \cos 2t $ and $\displaystyle y = 3t \sin 2t $.
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