Average Value

**VkL** · May 27th 2009, 09:45 AM

If the average value of f on the interval 2 < or = x < = 5 is 4, Find integral form 2 to 5 of (3(f(x) + 2)dx

**HallsofIvy** · May 27th 2009, 10:14 AM

Originally Posted by VkL

If the average value of f on the interval 2 < or = x < = 5 is 4, Find integral form 2 to 5 of (3(f(x) + 2)dx

The "average" value of a function, f, on the interval $a\le x\le b$ is $\frac{\int_a^b f(x)dx}{b-a}$ so knowing that the average of f on [tex]a\le x\le 5[/itex] is 4 tells you that $\frac{\int_2^5 f(x)dx}{3}= 4$ so $\int_2^5 f(x)dx= 4(3)= 12$ .
$\int_2^5 (3f(x)+ 2)dx= 3\int_2^5 f(x)dx+ 2\int_2^5 dx$ .

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