Show that the limit as (x,y) -> 0 doesn't exist.

Attempt:

To prove it, I must use thedefinitionof limit (the epsilon and delta thing).

Well, if the limit exists, and is 1, given any $\displaystyle \epsilon >0$ we can find a $\displaystyle \delta >0$ such that $\displaystyle \sqrt{x^2 + y^2} < \delta$ if $\displaystyle |f(x,y) -1| < \epsilon$

perhaps we can ty $\displaystyle \epsilon = 1/2$

I'm not sure how to complete this proof to conclude that $\displaystyle \lim_{(x,y) \to (0,0)} f(x,y)$ doesn't exist... some help with this is very much appreciated.