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Math Help - easy limit problem

  1. #1
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    easy limit problem

    What is the limit as x-> infinity of arcsec(x)
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    y = arcsec(x) has x \in [-1,1] therefore can it approach infinity?
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  3. #3
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    so the limit does not exist?
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  4. #4
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    I think not.
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    Quote Originally Posted by IronMan21 View Post
    What is the limit as x-> infinity of arcsec(x)
    domain of y = arcsec(x) = \arccos\left(\frac{1}{x}\right) is (-\infty,-1] \cup [1, \infty)

    the limit as x \to \infty is \frac{\pi}{2}

    note the graph ...

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  6. #6
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    I was under the impression that

    y = arcsec(x) = \frac{1}{arccos(x)}
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  7. #7
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    I have one more question. If the limit was approaching negative infinity, wouldn't the answer also be pi/2? But that wouldn't make sense right?
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  8. #8
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    Quote Originally Posted by IronMan21 View Post
    I have one more question. If the limit was approaching negative infinity, wouldn't the answer also be pi/2? But that wouldn't make sense right?
    look at the graph
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  9. #9
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    wow im so stupid thanks
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