What is the limit as x-> infinity of arcsec(x)
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$\displaystyle y = arcsec(x) $ has $\displaystyle x \in [-1,1]$ therefore can it approach infinity?
so the limit does not exist?
I think not.
Originally Posted by IronMan21 What is the limit as x-> infinity of arcsec(x) domain of $\displaystyle y = arcsec(x) = \arccos\left(\frac{1}{x}\right)$ is $\displaystyle (-\infty,-1] \cup [1, \infty)$ the limit as $\displaystyle x \to \infty$ is $\displaystyle \frac{\pi}{2}$ note the graph ...
I was under the impression that $\displaystyle y = arcsec(x) = \frac{1}{arccos(x)}$
I have one more question. If the limit was approaching negative infinity, wouldn't the answer also be pi/2? But that wouldn't make sense right?
Originally Posted by IronMan21 I have one more question. If the limit was approaching negative infinity, wouldn't the answer also be pi/2? But that wouldn't make sense right? look at the graph
wow im so stupid thanks
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