1. ## Integration Problem

Is there any way to integrate the following?:

$\int \frac{dx}{\sqrt{a^{-1}-x^{-1}}}$

(Where "a" is a constant.)

Any help would be appreciated.

2. Originally Posted by GarmGarf
Is there any way to integrate the following?:

$\int \frac{dx}{\sqrt{a^{-1}-x^{-1}}}$

(Where "a" is a constant.)

Any help would be appreciated.
Ok that is the same with

$\int \frac{dx}{\sqrt{1/a-1/x}}}$

I hope this helps

3. Originally Posted by GarmGarf
Is there any way to integrate the following?:

$\int \frac{dx}{\sqrt{a^{-1}-x^{-1}}}$

(Where "a" is a constant.)

Any help would be appreciated.

Fist we would need to simplfy to get

$\frac{1}{\sqrt{\frac{1}{a}-\frac{1}{x}}}=\frac{1}{\sqrt{\frac{x-a}{ax}}}=\frac{\sqrt{ax}}{\sqrt{x-a}}$

So we have the integral

$\sqrt{a}\int \frac{\sqrt{x}}{\sqrt{x-a}}dx$

Now we let $x=a\sec^2(t) \implies dx=2a\sec(t)[\sec(t)\tan(t)]dt$

$\sqrt{a}\int \frac{\sqrt{x}}{x-a}dx=\sqrt{a}\int \frac{\sqrt{a}\sec(t)}{\sqrt{a\sec^2(t)-a}}(2a\sec^2(t)\tan(t)dt)=$

$2a^{\frac{3}{2}}\int \sec^{3}(t)dt$

Here is how you integrate $\sec^{3}(t)$

Integral of secant cubed - Wikipedia, the free encyclopedia

So we get

$2a^{3/2}\left[\frac{1}{2}\sec(t)\tan(t)+\frac{1}{2}\ln|\sec(t)+\ tan(t)| \right]$

From here we just need to back substitue

$x=a\sec^2(t) \iff \frac{x}{a}=\sec^2(t) \iff \frac{x}{a}=\tan^2(t)+1$

$\tan^2(t)=\frac{x-a}{a} \iff \tan(t)=\sqrt{\frac{x-a}{a}}$ and of course

$\sec(t) =\sqrt{\frac{x}{a}}$

I will leave the rest to you