Thread: Rolle's Theorem

Hello I have some question about the Rolle's theorem

Here is the question:
Use Rolle's theorem to show that f(x)=x^3+3x-5 has exactly one real root.

what is my limit!?I need some limit right!?

Thanks
NaNa

Originally Posted by NaNa

Hello I have some question about the Rolle's theorem

Here is the question:
Use Rolle's theorem to show that f(x)=x^3+3x-5 has exactly one real root.

what is my limit!?I need some limit right!?

Thanks
NaNa

No note quite.

Suppose by way of contradiction that

note that

Now if you apply Rolle's theorem



Now we have a problem since

That mean that this is a contradiction because there is no real number c that fits the bill.

So this is Half of the proof. We have show that there cannot be more than two roots, it is still up to you to show that there is at least one.

Good luck.

Not to put too fine of a point on it but




is a statement of the mean value theorem which granted is prooved using Rolle's Thm

But we don't need the MVT for this problem

Rolles theorem states if f(a) = f(b) = 0 under the proper continuity and differentiability conditions then there is at least one point c where
f ' (c) = 0

As stated assume f(a) = f(b) = 0

Therefore and the results follows as stated

Originally Posted by Calculus26

Not to put too fine of a point on it but




is a statement of the mean value theorem which granted is prooved using Rolle's Thm

But we don't need the MVT for this problem

Rolles theorem states if f(a) = f(b) = 0 under the proper continuity and differentiability conditions then there is at least one point c where
f ' (c) = 0

As stated assume f(a) = f(b) = 0

Therefore and the results follows as stated

Thanks I got a little a head of my self . Thanks again

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