I decided to add another 3, so its 6 problems
please help if anyone knows how to solve these,
answers would be appreciated greately
these are very straight-forward, basic derivative problems using the chain rule. use the following derivative rules (which you should already know) ...
$\displaystyle \frac{d}{d\theta} \sin{u} = \cos{u} \cdot \frac{du}{d\theta}$
$\displaystyle \frac{d}{d\theta} \cos{u} = -\sin{u} \cdot \frac{du}{d\theta}$
$\displaystyle \frac{d}{dt} ke^u = ke^u \cdot \frac{du}{dt}$