Consider the inversion f(z)=1/z. What happens to the line y=2 under this mapping?
In such a question the way to solve them is:
1/z=1/(x+iy)=(x-iy)/(x^2+y^2)
so u= x/(x^2+y^2) and v=(-y)/(x^2+y^2)
so x= u/(u^2+v^2) y=-v/(u^2+v^2)
u^2 + v^2 +v/2=0 by complete the square
=> u^2+(v+1/4)^2=1/16
so the center is(0,1/4) ad my radius = 1/root(16)?
Thanks