# Math Help - derivative

1. ## derivative

Just want to check if I did it right: Thanks
y=2∜(x^3 )
=x^3/2
=1/2(x^3)
=3x^2/2

2. $y=2\sqrt[4]{x^3}=2x^{3/4}$ so $y'=\frac{3}{2}x^{-1/4}$