# derivative

• May 25th 2009, 07:55 AM
lisa1984wilson
derivative
Just want to check if I did it right: Thanks
y=2∜(x^3 )
=x^3/2
=1/2(x^3)
=3x^2/2
• May 25th 2009, 08:16 AM
Spec
$y=2\sqrt[4]{x^3}=2x^{3/4}$ so $y'=\frac{3}{2}x^{-1/4}$