Just want to check if I did it right: Thanks

y=2∜(x^3 )

=x^3/2

=1/2(x^3)

=3x^2/2

Printable View

- May 25th 2009, 07:55 AMlisa1984wilsonderivative
Just want to check if I did it right: Thanks

y=2∜(x^3 )

=x^3/2

=1/2(x^3)

=3x^2/2

- May 25th 2009, 08:16 AMSpec
$\displaystyle y=2\sqrt[4]{x^3}=2x^{3/4}$ so $\displaystyle y'=\frac{3}{2}x^{-1/4}$