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Math Help - f(x)= A sin(b(x-c))+d help solve

  1. #1
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    f(x)= A sin(b(x-c))+d help solve

    f(x)=A sin(b(x-c))+d
    we have to find the values of A,b,c,d and have been given the points (4,6) (62,6)
    we also know that f'(33)=0 and f'(4)=2/3

    any help would be appreciated
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  2. #2
    Senior Member apcalculus's Avatar
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    Quote Originally Posted by jacksback View Post
    f(x)=A sin(b(x-c))+d
    we have to find the values of A,b,c,d and have been given the points (4,6) (62,6)
    we also know that f'(33)=0 and f'(4)=2/3

    any help would be appreciated
    We have four unknowns and four conditions. The first two conditions you can simply plug in:


    6 = A sin ( b (4-c)) + d

    6 = A sin (b (62-c)) + d

    For the two derivative conditions, you first find the derivative:

    f' = A cos (b (x-c)) b (by the chain rule)

    ... can you finish the rest?

    Good luck!
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