Hello all,

This is a differentiaiton question given to me by my friend.I could not find the mistake in the proof.

x = x

x = 1 + 1 + ... + 1(x times)

multiplying by x

x(x) = x(1 + 1 + ... + 1)

x2 = x + x + ... + x

D(x2) = D(x + x + ... + x)

D(x2) = D(x) + D(x) + ... + D(x)

2x = 1 + 1 + ... + 1(x times)

2x = x

2 = 1

i think it is somewhere in the differentiation .But couldnot get it.

i hope i have not made a mistake by posting in the wrong forum.