Find the Point(s), P(x,y) on the graph of y=4-x^2 so that the distance between two points P and Q(0,2) is a minimum.
i think what you do is
d=squareroot[(x-0)+(y-2)]
d^2=[(x-0)+(y-2)]
then you plug in either x or y and differentiate?
the answer is supposed to be sqareroot(3/2), -squareroot(3/2), and 5/2