Find the Point(s), P(x,y) on the graph of y=4-x^2 so that the distance between two points P and Q(0,2) is a minimum.

i think what you do is

d=squareroot[(x-0)+(y-2)]

d^2=[(x-0)+(y-2)]

then you plug in either x or y and differentiate?

the answer is supposed to be sqareroot(3/2), -squareroot(3/2), and 5/2