l don't understand the d/dx in front of the integral...

$\displaystyle \frac{d}{dx}\int^x_0 \frac{du}{1+u^{2}}$

= arctan 0 - arctan x

= -arctanx

could this be right?

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- May 20th 2009, 08:47 PMalgebra2Evaluate integral
l don't understand the d/dx in front of the integral...

$\displaystyle \frac{d}{dx}\int^x_0 \frac{du}{1+u^{2}}$

= arctan 0 - arctan x

= -arctanx

could this be right? - May 20th 2009, 09:24 PMTheEmptySet
- May 20th 2009, 10:33 PMmatheagle