A farmer has 100 yards of fencing to form 2 identical rectangular pens and a third pen that is twice as long as the other 2 pens. All three pens have the same width, x. Which value of y produces the maximum total fenced area?
A farmer has 100 yards of fencing to form 2 identical rectangular pens and a third pen that is twice as long as the other 2 pens. All three pens have the same width, x. Which value of y produces the maximum total fenced area?
all separate pens, I assume?
1st pen ...
2nd pen ...
3rd pen ...
use the perimeter equation to solve for x in terms of y, then sub into the area equation ... then maximize.
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Originally Posted by CalculusKing 
