# Thread: Differentiating a function of hyperbolic functions

1. ## Differentiating a function of hyperbolic functions

I don't know how to show this:

If $\displaystyle x_{1}(s) = 2\arcsin(\frac{s}{4}) + 2\frac{s}{4}\sqrt{1-\frac{s^{2}}{16}}$

Then
$\displaystyle x'_{1}(s)$$\displaystyle = \frac{1}{4}\sqrt{16-s^{2}} Can anyone help? Thanks. Obviously you are just differnetiating first using the rule for differentiating arcsin but then once I evaluate it all I do not get the required solution. 2. Originally Posted by bobby I don't know how to show this: If \displaystyle x_{1}(s) = 2\arcsin(\frac{s}{4}) + 2\frac{s}{4}\sqrt{1-\frac{s^{2}}{16}} Then \displaystyle x'_{1}(s)$$\displaystyle = \frac{1}{4}\sqrt{16-s^{2}}$

Can anyone help? Thanks.

Obviously you are just differnetiating first using the rule for differentiating arcsin but then once I evaluate it all I do not get the required solution.

Is that really "$\displaystyle 2\frac{s}{4}$"? That is, of course, just $\displaystyle \frac{s}{2}$ but I suspect that the "2" is not supposed to be there.

If it were just $\displaystyle x_{1}(s) = 2\arcsin(\frac{s}{4}) + \frac{s}{4}\sqrt{1-\frac{s^{2}}{16}}$ then $\displaystyle x_{1}'(x)= 2\frac{1/4}{\sqrt{1- \frac{s^2}{16}}}+ \frac{1}{4}\sqrt{1- \frac{s^2}{16}}+ \frac{s}{8}\frac{1}{\sqrt{1- s^2/8}}(-\frac{s}{8})$

Now, $\displaystyle \frac{1}{2}\frac{1}{\sqrt{1- \frac{s^2}{16}}}- \frac{s^2}{8}\frac{1}{1-\frac{s^2}{16}}$$\displaystyle = \frac{1}{2}\frac{1- \frac{s^2}{16}}{\sqrt{1- \frac{x^2}{16}}}$$\displaystyle = \frac{1}{2}\sqrt{1- \frac{s^2}{16}}$

3. Originally Posted by HallsofIvy
Is that really "$\displaystyle 2\frac{s}{4}$"? That is, of course, just $\displaystyle \frac{s}{2}$ but I suspect that the "2" is not supposed to be there.

If it were just $\displaystyle x_{1}(s) = 2\arcsin(\frac{s}{4}) + \frac{s}{4}\sqrt{1-\frac{s^{2}}{16}}$ then $\displaystyle x_{1}'(x)= 2\frac{1/4}{\sqrt{1- \frac{s^2}{16}}}+ \frac{1}{4}\sqrt{1- \frac{s^2}{16}}+ \frac{s}{8}\frac{1}{\sqrt{1- s^2/8}}(-\frac{s}{8})$

Now, $\displaystyle \frac{1}{2}\frac{1}{\sqrt{1- \frac{s^2}{16}}}- \frac{s^2}{8}\frac{1}{1-\frac{s^2}{16}}$$\displaystyle = \frac{1}{2}\frac{1- \frac{s^2}{16}}{\sqrt{1- \frac{x^2}{16}}}$$\displaystyle = \frac{1}{2}\sqrt{1- \frac{s^2}{16}}$
I'm reading it from a past paper and it does have the '2' in front of the $\displaystyle \frac{s}{4}$ strangely. Either way, i'm not sure on a couple of parts of your method.

Firstly,

In the 1st line of the differentiation, the 3rd term, I am unsure of why there is an $\displaystyle \frac{s^{2}}{8}$ in the square root, should this not be over 16?

Secondly,

I do not understand how you went from the first line to $\displaystyle \frac{1}{2}\frac{1}{\sqrt{1- \frac{s^2}{16}}}- \frac{s^2}{8}\frac{1}{1-\frac{s^2}{16}}$

$\displaystyle \frac{1}{2}\frac{1}{\sqrt{1- \frac{s^2}{16}}}$ is obvious but the other part is not so clear.