You have,

Thus,

You can write,

Slope is 1, Intercept is 0.

Thus, you need to find the point(s) where the derivative (slope) of the normal line is -1. The reason why -1 is because if the derivative istangentto the curve, but you need thenormalline. Which is found by taking the reciprocal of the slope and making it change signs. In this case one.

Thus, find all such that,

Where,