# distance between two skew lines.

• May 20th 2009, 01:17 AM
qkfxjs
distance between two skew lines.
Find the distance between two skew lines:
L1: x = 2s, y = 2s - 1, z = s + 1, and
L2: x = t, y = 2t - 2, z = 3.
• May 20th 2009, 07:40 AM
Plato
Quote:

Originally Posted by qkfxjs
Find the distance between two skew lines:
L1: x = 2s, y = 2s - 1, z = s + 1, and L2: x = t, y = 2t - 2, z = 3.

If $P+tD~\&~Q+sE$ are two skew lines, the the distance between them is $\frac{{\left| {\overrightarrow {PQ} \cdot \left( {D \times E} \right)} \right|}}{{\left\| {\left( {D \times E} \right)} \right\|}}$
• May 20th 2009, 08:53 AM
qkfxjs
Ok
So how can I solve the problem.

I'm still having a problem.
• May 20th 2009, 09:15 AM
Plato
Quote:

Originally Posted by qkfxjs
So how can I solve the problem.

Find the direction vector of each line. Those are $D~\&~E$.

Find a point on each line. Those are $P~\&~Q$

Then use the formula.