# Tough Integral.

• May 19th 2009, 08:34 PM
justchillin
Tough Integral.

Is this correct?

Cause the texbook gives.

$(b^{b}a^{-a})^{\frac{1}{b-a}}e^{-1}$

The original question is at the bottom on the picture i posted.
• May 19th 2009, 11:21 PM
Isomorphism
Yes thats correct. You can simplify your answer to the one given in the textbook. Remember that $e^{\ln x} = x$ $\, \,$ !
• May 19th 2009, 11:23 PM
matheagle
correction x not x!, sry, just had to do it (Lipssealed)

Quote:

Originally Posted by Isomorphism
Yes thats correct. You can simplify your answer to the one given in the textbook. Remember that $e^{\ln x} = x$!