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Math Help - projectile motion

  1. #1
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    projectile motion

    A fast bowler runs in to bowl and releases the ball froma height of 2.4m above the ground at a speed of 144km/h at an angle of 7 degrees below the horizontal. Take the origin to be the point where the ball is released and g=-10m/s/s.
    (a) show that the coordinates of the ball after t seconds is given by

    1) x=40t cos 7 and
    2) y=2.4-40t sin 7-5t^2

    My question is where did the 40 come from and where has the velocity of 144km/h gone?

    Thank you
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  2. #2
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    Quote Originally Posted by slaypullingcat View Post
    A fast bowler runs in to bowl and releases the ball froma height of 2.4m above the ground at a speed of 144km/h at an angle of 7 degrees below the horizontal. Take the origin to be the point where the ball is released and g=-10m/s/s.
    (a) show that the coordinates of the ball after t seconds is given by

    1) x=40t cos 7 and
    2) y=2.4-40t sin 7-5t^2

    My question is where did the 40 come from and where has the velocity of 144km/h gone?

    Thank you
    unit conversion ...

    144 km/hr = 40 m/s
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  3. #3
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    Ha, jeez i'm thick some times. Cheers.
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