Okay, I am completely stumped on this problem. Do I have to use tan^-1 somehow? dy ----------- y(√5y^2-3) Thanks guys! this is the last one
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Have you learned partial fractions? Using y = 0, we isolate A Play some algebra tricks Use y = 0 again From here we've completed the decomposition, C will just be 0. Use a u-sub
Okay my teacher posted up the answers online and this is what he got. (√3) tan^-1(√3(5y^2-3)/3) ----------------------------- 3 how did he get to that answer?
Did I copy the original question correctly? You can work backwards and see that your teacher's answer is clearly not the same integral.
For the equation I wrote down, the square root is supposed to go across 5y^2-3 entirely as opposed to just 5y^2. We haven't learned partial fractions yet. I think he just wants u-substitution?
So that's If so, than yes, i'm getting an arctan, but still not quite this answer
yea, maybe he made a mistake; he does that a lot actually. How did you work through that problem? Thanks for all your help by the way.
Actually, your answer is the right answer. I just typed the answer in incorrectly.
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