ok... i was given this function:
f(x) = (x+2)^3 (1-x) (3-x)
and i have some trouble getting it's critical points...
I understand i get those by finding the points in which the derivative is 0.... right?
I got the derivative....
f'(x) = 5x^4 -8x^3 -27x^2 -44x +4
so... i equaled that to zero... and i got the four points, which are:
x1 = 2.314
x2 = -2.005
x3 = -1.995
x4 = 0.086
so the question is... does that even make any sense? I checked those points on the graph, and they dont mark the minimum values or anything... am i doing something wrong??