hi!

ok... i was given this function:

f(x) = (x+2)^3 (1-x) (3-x)

and i have some trouble getting it's critical points...

I understand i get those by finding the points in which the derivative is 0.... right?

I got the derivative....

f'(x) = 5x^4 -8x^3 -27x^2 -44x +4

so... i equaled that to zero... and i got the four points, which are:

x1 = 2.314

x2 = -2.005

x3 = -1.995

x4 = 0.086

so the question is... does that even make any sense? I checked those points on the graph, and they dont mark the minimum values or anything... am i doing something wrong??