So in calculus 2 they have this problem that I am just stuck with r=2+3sinΘ I multiply both sides by r r^2 = 2r + 3rsinΘ that turns to be x^2 + y^2 = 2r + 3y x^2 + y^2 - 3y = 2r how do I get rid of the last r?
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Originally Posted by fhtapia So in calculus 2 they have this problem that I am just stuck with r=2+3sinΘ I multiply both sides by r r^2 = 2r + 3rsinΘ that turns to be x^2 + y^2 = 2r + 3y x^2 + y^2 - 3y = 2r how do I get rid of the last r?
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