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About LinkBacksThe equation of a cirlce isOriginally Posted by Solid8Snake
where 3 is the radius of the circle
If they respect no mans land it will incerase by .1 so the new equaition would be
^2+(y+5)^2 \le (3.1)^2 )
To organize a military exercise, a drill sergeant designates an enemy territory represented by the inequality (x-2)^2+(y+5)^2 (less than or equal to 9) on the map of the base, whose axes are scaled in kilometers. If the soldiers respect a no man's land of 0.1km, what relation represents the friendly territory?
Plz explain.
THX in advance
Your inequality describes the area of a circle (circle line included) with the center C(2, -5) and the radius r = 3.
If the soldiers keep a distance of more than 3.1 km to C then they are in the friendly area:
^2+(y+5)^2 > (3.1)^2)
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