given that x=120 sin (pi/12)t , what is the first time when the particle is (i) 30m to the right of the origin and (ii) 30m to the left of the origin?
30=120 sin (pi/12)t
t=(1/4) / sin (pi/12)
t=0.96592..... is this correct?
I don't know how to think about the second part when x=-30. Is it more complicated or do I just solve it as above?