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- May 17th 2009, 06:37 PM #1

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- Jan 2009
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## SHM

given that x=120 sin (pi/12)t , what is the first time when the particle is (i) 30m to the right of the origin and (ii) 30m to the left of the origin?

Im thinking

30=120 sin (pi/12)t

1/4=sin (pi/12)t

t=(1/4) / sin (pi/12)

t=0.96592..... is this correct?

I don't know how to*think*about the second part when x=-30. Is it more complicated or do I just solve it as above?

Thank you

- May 17th 2009, 06:50 PM #2

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