$\displaystyle \int\frac{3x}{(x-1)(x^2+6)}$

I got this far-

$\displaystyle \int\frac{3x}{(x-1)(x^2+6)} = \frac{A}{x-1}+\frac{Bx+C}{x^2+6}$

But after that I don't know how to solve for it because of the Bx+C

Any help is appreciated! Test tomorrow and I need to know this...