# Thread: Help with solving diff. equation

1. ## Help with solving diff. equation

Hey everybody,

Just need some help gettin through this one. I've gotten through most of the work, but I'm not getting the right conclusion. So, maybe my work is wrong. Would anyone mind giving me a second angle on this?

ye^-x(dy/dx) + 2 = 0: y = 2 when x = 0

Any help is greatly appreciated. Thanks.

2. Originally Posted by Worthey1987
Hey everybody,

Just need some help gettin through this one. I've gotten through most of the work, but I'm not getting the right conclusion. So, maybe my work is wrong. Would anyone mind giving me a second angle on this?

ye^-x(dy/dx) + 2 = 0: y = 2 when x = 0

Any help is greatly appreciated. Thanks.
separable ...

$y \, dy = -2e^x \, dx$

$\frac{y^2}{2} = -2e^x + C$

$y^2 = -4e^x + C_2$

$y = \sqrt{C_2 - 4e^x}$

$2 = \sqrt{C_2 - 4}$

$C_2 = 8$

$y = \sqrt{8 - 4e^x}$