compute the double integral from [0,sqrt(pi)]x[x,sqrt(pi)] how can I compute sin(y^2)
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Originally Posted by yzc717 compute the double integral from [0,sqrt(pi)]x[x,sqrt(pi)] how can I compute sin(y^2) Can you explain the limits more clearly. CB
Hello, One can guess that and that is Reverse the order of the integrals (which is possible since the integrand is positive) : y ranges from 0 to x varies from 0 to y. So the integral is now : And that's easier
Originally Posted by Moo And that's easier that's what I got, I suddenly forget how to compute the sin(y^2)...
The inner integral will give y. Which finally gives For this one : substitution !
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