1. ## Table of Integral

I need to figure out how to derive it. I know you use partial fractions, but again with no numbers, the letters always change, part of it is my dyslexia.. thank you.

2. ̣Use partial fraction treat a and b as simple numbers. It will work out.

̣

3. Originally Posted by Collegeboy110
I need to figure out how to derive it. I know you use partial fractions, but again with no numbers, the letters always change, part of it is my dyslexia.. thank you.

$\frac{d+cx}{(x-a)(x-b)}=\frac{A}{x-a}+\frac{B}{x-b}\Rightarrow d+cx=A(x-b)+B(x-a)$ so A+B=c and -Ab-aB=d

So $A=\frac{ac+d}{a-b}$ and $B=-\frac{bc+d}{a-b}$

From here you should be okay

4. I get this part, but I cant do the next step.

5. so $\int\frac{d+cx}{(x-a)(x-b)}dx=\int[\frac{ac+d}{(a-b)(x-a)}-\frac{bc+d}{(a-b)(x-a)}]dx=$ what we want it to be