# Table of Integral

• May 16th 2009, 05:07 PM
Collegeboy110
Table of Integral
http://i49.photobucket.com/albums/f271/NAKo110/10.gifI need to figure out how to derive it. I know you use partial fractions, but again with no numbers, the letters always change, part of it is my dyslexia.. thank you.
• May 16th 2009, 05:55 PM
Banned for attempted hacking
̣Use partial fraction treat a and b as simple numbers. It will work out.

̣
• May 16th 2009, 06:03 PM
artvandalay11
Quote:

Originally Posted by Collegeboy110
http://i49.photobucket.com/albums/f271/NAKo110/10.gifI need to figure out how to derive it. I know you use partial fractions, but again with no numbers, the letters always change, part of it is my dyslexia.. thank you.

$\displaystyle \frac{d+cx}{(x-a)(x-b)}=\frac{A}{x-a}+\frac{B}{x-b}\Rightarrow d+cx=A(x-b)+B(x-a)$ so A+B=c and -Ab-aB=d

So $\displaystyle A=\frac{ac+d}{a-b}$ and $\displaystyle B=-\frac{bc+d}{a-b}$

From here you should be okay
• May 18th 2009, 07:50 PM
Collegeboy110
I get this part, but I cant do the next step.
• May 18th 2009, 08:30 PM
artvandalay11
so $\displaystyle \int\frac{d+cx}{(x-a)(x-b)}dx=\int[\frac{ac+d}{(a-b)(x-a)}-\frac{bc+d}{(a-b)(x-a)}]dx=$ what we want it to be