A golfer hits a ball from point A with initial velocity 24.5 m/s at and angle above the horizontal, where sin = 0.8. The ball just clears the tops of the two trees. The tops of the trees are both 14.7m above the level of a and are horizontal distance dm apart.
a i) Find the time taken for the ball to reach the top of the first tree.
ii) Determine the value of d.
Ok i have worked this question out but i'm not confident the answer is right as i found it very hard. This is what i did.
v = 24.5
sin = 0.8
tree h = 14.7
so using trig i get 14.7/hypotenuse = 0.8
hypotenuse = 14.7/0.8 = 18.475
cos = adjacent/18.375
cos = 0.6
t = 3 or t=1
so t=1 at top of first tree.
time to second tree = 3
where = distance to second tree
could anybody confirm this is done right? or tell me where i have gone wrong if not?