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Math Help - taylor series

  1. #1
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    taylor series

    cos (2x^2)-1/x^2 at x=0
    f^(10) (0) = ?? (basically the 10th derivative)

    I would appreciate it if someone could help me with this. I found C10 which is: 3^6/6! but I don't know what to do from there..


    Thank you
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by thehabsonice View Post
    cos (2x^2)-1/x^2 at x=0
    f^(10) (0) = ?? (basically the 10th derivative)

    I would appreciate it if someone could help me with this. I found C10 which is: 3^6/6! but I don't know what to do from there..


    Thank you
    you should set out your problem more clearly. do you mean \frac {\cos 2x^2 - 1}{x^2} or \cos 2x^2 - \frac 1{x^2}?

    anyway, here's a hint: \cos 2x^2 = \sum_{n = 0}^\infty (-1)^n \frac {(2x^2)^{2n}}{(2n)!}

    can you use that?
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