Fill in the following table to find $\displaystyle \lim_{x\to-2}f(x)$ where $\displaystyle f(x)=\frac{x^3+2x^2-x-2}{x^2-4}$. Give table values tofour signifigant digits.

_x__-2.5__-2.1__-2.01__-2.002__-2.0001__-2.00001__-2

f(x)_____________________________________________?

_x__-1.5__-1.9__-1.99__-1.999__-1.9999__-1.99999__-2

f(x)_____________________________________________?

Based on this table, to two significant digits, for $\displaystyle \lim_{x\to-2}f(x)=$__my estimate?___

Anybody?

Hey guys. I can pretty much do the table, but I put it up there so that you guys would understand that we are evaluating the limit, not algebraically. That's why we were asked to give an answer to with the given margin of error. Anybody got any ideas ?numerically

Is this a bad question or something? usually I get a much quiker response.