Find the tangents at the pole for r=2(1-sin theta)
I've been having alot of trouble with this concept. So far Ive tried setting r= to 0 and solving for theta but i dont know if thats right...
There's a little more to it than that.
$\displaystyle \frac{dy}{dx}=\frac{rcos(t)+sin(t)\cdot\frac{dr}{d t}}{-rsin(t)+cos(t)\cdot\frac{dr}{dt}}$
Find the derivative of $\displaystyle r=2(1-sin(t))$ and plug it all in.
Then, set to 0 and solve for theta.
I just used t for less typing.
Upon doing all that, you should get $\displaystyle \frac{sin(2t)-cos(t)}{cos(2t)+sin(t)}$
Just set $\displaystyle sin(2t)-cos(t)=0$ and solve for t.
Spoiler: