find the area of the interior of r=1sin theta
(above the polar axis)
i think it is pi/4 but i also got pi/8 and i'm not sure which one, or if either, is right... thank you in advance to anyone who helps
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find the area of the interior of r=1sin theta
(above the polar axis)
i think it is pi/4 but i also got pi/8 and i'm not sure which one, or if either, is right... thank you in advance to anyone who helps
Is this what you're looking for?.
This gives the area from 0 to Pi. In other words, the smaller portion above the 'xaxis', so to speak.
yeah. i did it from 0 to pi/2 though...why is it pi?
I just integrated from 0 to Pi. You can do it from 0 to Pi/2 and multiply by 2 as well to get the same thing.
The problem said area above the polar axis. It starts at what we can say is the positive xaxis and turns counterclockwise to Pi so that it encompasses all the area above the polar axis. After you pass Pi(180 degrees) you get below it. I shaded the wanted region, but it did not appear when I saved it to post. Sorry 'bout that.
Hello, andyaddition!
Did you make a sketch?
This is a cardioid . . .Quote:
Find the area of the interior of (above the polar axis)
Code:
..*..  ..*..
*:::::::*  *:::::::*
  *      *      *  
*  *

*  *
*  *
*  *

*  *
*  *
*  *
*  *
* * *

We can find the area from to . . . and double.
So we have:.
I get: .
thank you both very much