I am trying to integrate the function
1/SQRT[u(au-b)(au-b)-4u]
between 0 and 1 with no success even though I have tried several transformations.

I would appreciate if anybody has an opinion.

Regards

2. Originally Posted by oguzkan
I am trying to integrate the function
1/SQRT[u(au-b)(au-b)-4u]
between 0 and 1 with no success even though I have tried several transformations.

I would appreciate if anybody has an opinion.

Regards
Just for clarification, is it

$\int_0^1 \frac{du}{\sqrt{u(au-b)^2-4u}}$

and are $a$ and $b$ arbitrary constants?

3. Hi Danny,

Yes. That is the form and yes a and b can be treated as arbitrary constants independent of u.

Thank you for the quick reply.

Regards