I am trying to integrate the function 1/SQRT[u(au-b)(au-b)-4u] between 0 and 1 with no success even though I have tried several transformations. I would appreciate if anybody has an opinion. Regards
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Originally Posted by oguzkan I am trying to integrate the function 1/SQRT[u(au-b)(au-b)-4u] between 0 and 1 with no success even though I have tried several transformations. I would appreciate if anybody has an opinion. Regards Just for clarification, is it $\displaystyle \int_0^1 \frac{du}{\sqrt{u(au-b)^2-4u}}$ and are $\displaystyle a$ and $\displaystyle b$ arbitrary constants?
Hi Danny, Yes. That is the form and yes a and b can be treated as arbitrary constants independent of u. Thank you for the quick reply. Regards
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