Hi I am a bit confused on how to differentiate a fraction like the problem: integral of 2 / (3 x^1/3) dx Im not sure where to start can you pull the 2/3 out front and just make it: 1/ x^1/3? and take ln of x^1/3? Please help?
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Originally Posted by craziebbygirl Hi I am a bit confused on how to differentiate a fraction like the problem: integral of 2 / (3 x^1/3) dx Im not sure where to start can you pull the 2/3 out front and just make it: 1/ x^1/3? and take ln of x^1/3? Please help? the natural log only comes into play if you have 1/x, which you do not have. note that . now integrate that using the power rule for integrals
Thanks! so would the answer be 1/2 x^4/3 + c?
also: I have the problem: find the integral of (5x - 6) / (square root of X) dx Can you separate it into 5x / X^1/2 - 6/x^1/2? even if I do that I still don't see how to solve it?
Originally Posted by craziebbygirl Thanks! so would the answer be 1/2 x^4/3 + c? no. look at the rule again. note that you have a negative 1/3 power. Originally Posted by craziebbygirl also: I have the problem: find the integral of (5x - 6) / (square root of X) dx Can you separate it into 5x / X^1/2 - 6/x^1/2? even if I do that I still don't see how to solve it? please post one problem per thread. Hint:
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