The derivitive of
f(x) = e^(kx) -√2x (x is out of the square root)
and the graph of f(x) has a stationary point at x=1 when k is a positive real number.
1) show the value of k=log e(√2)
2) if the graph of f(x) is passing through (0,0) find the rule foor f(x)
note: in the part "k=log e(√2)" e is the base
please explain me how to solve this,
Thanks in advance!