I am learning calculus at home during my summer break.In my current lesson, here's the problem:Let 2x squared y + y squared = cos x.Find dy/dx.The solution is dy/dx = -sinx -4xy/2x squared + 2yThe intermediate steps:2x^2 dy/dx + y(4x) + 2y dy/dx = -sin xdy/dx(2x^2 + 2y)= -sin x - 4xyWhy is there dy/dx only for 2x squared and 2y and not -sin x and y(4x)?Any light you could shed on this would be greatly appreciated.Carrie