Hi all!

Can someone help me with this exercise? I don't know how to start

Calculate the equation in finite differences of:

14x[n]-9x[n-1]+x[n-2]=70delta[n+3]-10delta[n+2]

Thanks in advance

Greetings

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- May 12th 2009, 09:45 AMAngusEquation in finite differences
Hi all!

Can someone help me with this exercise? I don't know how to start

Calculate the equation in finite differences of:

14x[n]-9x[n-1]+x[n-2]=70delta[n+3]-10delta[n+2]

Thanks in advance

Greetings - May 22nd 2009, 09:35 AMMedia_ManSimple Substitution
First, realize that $\displaystyle \Delta_n=x_{n+1}-x_n$ by definition. So, substitute:

$\displaystyle 14x_n-9x_{n-1}+x_{n-2}=70(x_{n+4}-x_{n+3})-10(x_{n+2}-x_{n+1})$

The way recursive formulas are defined is by relating $\displaystyle x_n$ to a formula involving several values $\displaystyle x_k$ for $\displaystyle k<n$, so we want to isolate the x with the highest subscript, in this case, $\displaystyle x_{n+4}$.

$\displaystyle x_{n+4}=\frac{1}{70}(80x_{n+3}-10x_{n+2}+0x_{n+1}+14x_n-9x_{n-1}+x_{n-2})$

More formally,

$\displaystyle x_{n+6}=\frac{1}{70}(80x_{n+5}-10x_{n+4}+0x_{n+3}+14x_{n+2}-9x_{n+1}+x_n)$ for all $\displaystyle n\in\mathbb{N}$

Therefore, to actually find the terms in this sequence, we would need to know the first six values of the sequence.