Could some please explain how to take this limit?
lim x ->2/3 1/(3x-2)^3
and a similar one
lim x ->2/3 7/(3x-2)^2
Thanks,
Printable View
Could some please explain how to take this limit?
lim x ->2/3 1/(3x-2)^3
and a similar one
lim x ->2/3 7/(3x-2)^2
Thanks,
lim x ->2/3 1/(3x-2)^3 yields 1/0 so the limit could be inf,-inf or DNE
So consider onesided limits
lim x ->2/3+ ( 1/(3x-2)^3) = infinity since if x > 2/3 3x-2 > 0 and
(3x-2)^3 > 0
lim x ->2/3- (1/(3x-2)^3) = neg infinity since if x < 2/3 3x-2 < 0 and
(3x-2)^3 < 0
Therefore lim x ->2/3 1/(3x-2)^3 DNE
Note if we had (3x-2)^2 then both limits would be infinity and the limit would be infinity
And the second one is infinity from both sides so the limit is positive infinity correct?
Ooops just saw the last line of your post. Thanks.
you got it--