May 12th 2009, 01:16 AM
show that y= Ae^kx+C is a solution of y'=k(y-C)
May 12th 2009, 01:52 AM
All times are GMT -8. The time now is
Copyright © 2005-2015 Math Help Forum. All rights reserved.
Copyright © 2005-2014 Math Help Forum. All rights reserved.