Could anyone help me with this monster? it's the integral 1/((x^4) + 4) dx Any help you could give would be Awesome!!!
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try a u substitution. that is, let u = (x^4) + 4 and then take the intergral of 1/u
Originally Posted by o&apartyrock try a u substitution. that is, let u = (x^4) + 4 and then take the intergral of 1/u Not possible since , and there is no term in the integral.
Where C and D are 1/4,
I tried messing with a u sub but didn't get anywhere. My prof said that this problem uses most of the techniques, as far as integral calc goes. He then went on to say that once you get past clac 2, this problem is easy. Thanks prof! lol
Originally Posted by derfleurer Where C and D are 1/4, Hmmmm... Thanks that helps me get going. This doesn't look like it's going to be fun though. hehehe.
Well I just checked wolfram, the answer they've got is Edit: Working backwards, that's Edit: Where the denominators of the inverse tangents are just disguised forms of the other denominators.
Originally Posted by redepoch7 Could anyone help me with this monster? it's the integral 1/((x^4) + 4) dx Any help you could give would be Awesome!!! let and then: and the rest is easy now.
Originally Posted by NonCommAlg let and then: and the rest is easy now. sorry but where did the 4 in the numerator of part one come from? Does it matter? Can you just factor that out? ex.
Originally Posted by redepoch7 sorry but where did the 4 in the numerator of part one come from? Does it matter? Can you just factor that out? ex. Since you were dealing with , follow NonCommAlg's suggestion, but then multiply your answer by .
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